Q15 of 184 Page 10

Find the value of K for which the points (8, 1), (k, -4), (2, -5) are collinear?

Given A(8, 1), B(k, -4) and C(2, -5) are collinear


To Find: Find the value of k


So, The given points are collinear, if are (∆ABC)=0


= Area of triangle =


Then,


= 8(1)+k(-6)+2(3) = 0


= 8 - 6k + 6 = 0


= -6k = -14


Hence, K =


More from this chapter

All 184 →
15

Find the value of K if the points A(2, 3), B(4, k) and C(6, -3) are collinear.

 15

Find the value of K for which the points (7, -2), (5, 1), (3, k) are collinear.

 15

Find the value of P are the points (2, 1), (p, -1) and (-1, 3)collinear?

 16

Show that the straight line joining the points A(0, -1) and B(15, 2) divides the line joining the points C(-1, 2)and D(4, -5) internally in the ratio 2:3.