A median of a triangle divides it into two triangles of equal area. Verify this result for
ABC whose vertices are A(1, 2), B(2, 5), C(3, 1).
Given a triangle whose vertices A(1, 2), B(2, 5), C(3, 1)
Let AD is the median on side BC

D will be the mid-point of segment BC. Therefore,
Coordinate of D ![]()
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Area of triangle ![]()
Then,
Area of triangle ABD ![]()
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sq units
Area of triangle ACD ![]()
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sq units
Hence, ∆ABD = ∆ACD
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