Q15 of 184 Page 10

Find the value of K for which the points (7, -2), (5, 1), (3, k) are collinear.

Given A(7, -2), B(5, 1) and C(3, k) are collinear


To find: Find the value of K


So, The given points are collinear, if are (∆ABC)=0


= Area of triangle =


Then,


= 7 – 7k +5k+10-9 = 0


= -2k + 8 = 0


Hence, K = 4


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