Q2 of 184 Page 10

Find the area of the quadrilateral whose vertices are

Given (0, 0), (6, 0), (4, 3), and (0, 3)


To Find: Find the area of quadrilateral.


Let us Assume A(x1, y1) = (0, 0)


Let us Assume B(x2, y2) = (6, 0)


Let us Assume C(x3, y3) = (4, 3)


Let us Assume D(x4, y4) = (0, 3)


Let us join Ac to from two triangles ∆ABC and ∆ACD


Now


Area of triangle


Then,


Area of given triangle ABC




= 9 Square units


Area of given triangle ABC




= 6 square units


Area of quadrilateral ABCD = Area of ABC + Area of ACD


= 9 + 6


Hence, Area = 15 sq units.


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