Q3 of 184 Page 10

Find the area of the quadrilateral whose vertices taken in order are (- 4, -2), (-3, -5), (3, -2) and (2, 3).

Given: The vertices of the quadrilateral be A(-4, -2), B(-3, -5), C(3, -2) and D(2, 3).


Let join AC to form two triangles,



Now, We know that


Area of triangle


Then,


Area of triangle ABC



Square Units


Now, Area of triangle ACD



Square Units


Area of quadrilateral ABCD = Area of triangle ABC+ Area of triangle ACD




Hence, Area of quadrilateral ABCD = 28 square Units


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