Q15 of 184 Page 10

Find the value of K if the points A(2, 3), B(4, k) and C(6, -3) are collinear.

Given A(2, 3), B(4, k) and C(6, -3) are collinear

To find: Find the value of K

So, The given points are collinear, if are (∆ABC)=0

= Area of triangle =

Then,

= 2k+6 - 24 +18 - 6k = 0

= -4k = 0

Hence, K = 0

Show that the point (a, 0), (0, b) and (1, 1) are collinear if

Find the values of x if the points (2x, 2x), (3, 2x+1) and (1, 0) are collinear.

Find the value of K for which the points (7, -2), (5, 1), (3, k) are collinear.

Find the value of K for which the points (8, 1), (k, -4), (2, -5) are collinear?