Q6 of 184 Page 10

Find the point on y - axis which is equidistant from the points A(6, 5) and B(- 4, 3).

Given points are A(6, 5) and B(- 4, 3).



We need to find a point on y - axis which is equidistant from these points.


Let us assume the point on y - axis be S(0, y).


We know that distance between the points (x1, y1) and (x2, y2) is .


From the problem,


SA = SB


SA2 = SB2


(0 - 6)2 + (y - 5)2 = (0 - (- 4))2 + (y - 3)2


(- 6)2 + (y - 5)2 = (4)2 + (y - 3)2


36 + y2 - 10y + 25 = 16 + y2 - 6y + 9


4y = 36



y = 9


The point on y - axis is (0, 9).


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