Prove that the points (3, 2), (6, 3), (7, 6), (4, 5) are the vertices of a parallelogram. Is it a rectangle?
Given points are A(3, 2), B(6, 3), C(7, 6) and D(4, 5).

We need to prove that these are the vertices of a parallelogram.
We know that in the lengths of opposite sides are equal in a parallelogram.
Let us find the lengths of the sides.
We know that the distance between the points (x1, y1) and (x2, y2) is
.
Now,
![]()
![]()
![]()
⇒ AB = √10
![]()
![]()
![]()
⇒ BC = √10
![]()
![]()
![]()
⇒ CD = √10
![]()
![]()
![]()
⇒ DA = √10
We got AB = CD and BC = DA, these are the vertices of a parallelogram.
Now we find the lengths of the diagonals.
![]()
![]()
![]()
⇒ AC = √32
![]()
![]()
![]()
⇒ BD = √8
We got AC≠BD.
∴ The points doesn’t form a rectangle.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.