use distance formula to show that the points (cosec2θ, 0), (0, sec2θ) and (1, 1) are collinear.
Given points are A(cosec2θ, 0), B(0, sec2θ ) and C(1, 1).

We need to check whether these points are collinear.
We know that for three points A, B and C to be collinear, the criteria to be satisfied is AB = AC + BC.
Let us find the distances first,
We know that distance between two points (x1, y1) and (x2, y2) is ![]()
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..... (1)
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.... - (2)
⇒ ![]()
⇒ ![]()
⇒
..... (3)
Now,
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⇒ AC + BC = AB
∴ The three points are collinear.
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