Prove that points (-3, -1), (2, -1), (1, 1) and (-2, 1) taken in order are the vertices of a trapezium.
Given: Points of the quadrilatreral A(-3, -1), B(2, -1), C(1, 1), and D(-2, 1).
To Prove: ABCD is a trapezium
Proof:
For proving ABCD to be a trapezium, we need to prove that two of the sides are parallel.
Therefore, AB and CD are parallel.
For proving ABCD a trapezium,
Slope of AB = Slope of CD
Slope of AB ![]()
Slope of CD ![]()
Hence, the quadrilateral is a trapezium.
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