If (6,8), (3,7) and (-2,-2) be the coordinates of the three consecutive vertices of a parallelogram, find coordinates of the fourth vertex.

Let the coordinates of the fourth vertex D be (x, y).
We know that diagonals of a parallelogram bisect each other.
∴ Midpoint of AC = Midpoint of BD …(i)
Coordinates of the midpoint of AC are
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Coordinates of the midpoint of BD are
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So, according to eq. (i), we have
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⇒ 3 + x = 4 and 7 + y = 6
⇒ x = 1 and y = -1
Thus, the coordinates of the vertex D are (1, -1)
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