Using the section formula, show that the points A (1,0), B (5,3), C (2,7) and D (–2, 4) are the vertices of a parallelogram taken in order.
The mid–point of diagonals AC and diagonal BD coincide.
Thus, Section Formula internally = 
Where l = 1 and m = 1
Mid–point of diagonal AC
A (1, 0) and C (2, 7)
The mid–point of diagonal is in the ratio of 1:1
= 
= 
= 
Mid–point of diagonal AC
B (5, 3) and D (–2, 4)
The mid–point of diagonal is in the ratio of 1:1
= 
= 
= 
Two diagonals are meeting at the same point. So, the given vertex forms a parallelogram.
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