Q14 of 112 Page 168

The equation of a straight line passing through the point (2 , –7) and parallel to x–axis is

The equation of the straight line passing through the point (x1 , y1) with slope as m is


(y–y1) = m(x–x1)


So here the straight line passing through the point (2,–7) and parallel to x axis is


(y–(–7)) = 0(x–2) (Slope of the line parallel to x axis is 0)


⇒ y + 7 = 0


⇒ y = –7

More from this chapter

All 112 →
12

The straight line 4x + 3y – 12 = 0 intersects the y– axis at

 13

The slope of the straight line 7y – 2x = 11 is equal to

 15

The x and y–intercepts of the line 2x – 3y + 6 = 0, respectively are

 16

The centre of a circle is (–6, 4). If one end of the diameter of the circle is at (–12, 8), then the other end is at