Q9 of 112 Page 166

Find the equation of the straight line perpendicular to the straight line x – 2y + 3 = 0 and passing through the point (1, –2).

Here it’s given that the straight line is perpendicular to the


straight line x – 2y + 3 = 0 and passing through the point (1, –2).


As the lines are perpendicular to each other , the product of their


slopes is equal to –1.


Slope of the given line x–2y + 3 = 0 is



Equation of the line passing through the point(1,–2) is


(y–y1) = m(x–x1),where (x1,y1) is (1,–2)


)


⇒ 2(y + 2) = (x–1)


⇒ 2y + 4 = x–1


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