The centroid of the triangle with vertices at (–2,– 5), (–2,12) and (10, – 1)is
Given the triangle with vertices at (–2,– 5),
(–2,12) and (10, – 1).
The centroid of the triangle ABC is ![]()
∴ centroid of the given ∆ABC is![]()
i.e.
= (2,2)
Couldn't generate an explanation.
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