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Q15 of 112 Page 168

The x and y–intercepts of the line 2x – 3y + 6 = 0, respectively are

The x –intercept can be found by substituting y = 0 in the equation 2x–3y + 6 = 0.


⇒ 2x –3(0) + 6 = 0


⇒ 2x + 6 = 0


⇒ 2x = –6


⇒


Now to calculate the y–intercept,substitute x = 0 in the equation 2x–3y + 6 = 0.


i.e.2(0)–3y + 6 = 0


⇒ –3y + 6 = 0


⇒ –3y = –6


⇒


∴ x–intercept is –3 and y– intercept is 2 i.e.(–3,2).

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Questions · 112
5. Coordinate geometry
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