The x and y–intercepts of the line 2x – 3y + 6 = 0, respectively are
The x –intercept can be found by substituting y = 0 in the equation 2x–3y + 6 = 0.
⇒ 2x –3(0) + 6 = 0
⇒ 2x + 6 = 0
⇒ 2x = –6
⇒ ![]()
Now to calculate the y–intercept,substitute x = 0 in the equation 2x–3y + 6 = 0.
i.e.2(0)–3y + 6 = 0
⇒ –3y + 6 = 0
⇒ –3y = –6
⇒ ![]()
∴ x–intercept is –3 and y– intercept is 2 i.e.(–3,2).
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