Q13 of 112 Page 163

Find the equation of the straight line passing through the point (3, 4) and has intercepts which are in the ratio 3 : 2.

Given that the intercepts are in the ratio 3:2


Let the x–intercept be 3k and 2k, where k is some constant


Using the intercept –form, the equation of the line is



⇒


⇒


The point (3, 4) lies on this line, thus the point will satisfy the equation of the line


⇒


⇒


⇒ 1 + 2 = k


⇒ K = 3


Thus the equation of the line is


⇒


⇒ 2x + 3y = 18


⇒ 2x + 3y –18 = 0


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