The side BC of an equilateral 3ABC is parallel to x–axis. Find the slope of AB and the slope of BC.
Slope of line BC:
The side BC is parallel to x–axis.
Slope of the side BC = 0.
Slope of line AB:
Since, this is an equilateral triangle each angle is 60°
∴ θ = 60°
m = tan θ
= tan 60°
= √3
Hence, the slope of AB is √3 and the slope of BC is 0
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