Q18 of 112 Page 168

The equation of a straight line parallel to y–axis and passing through the point (–2, 5) is

The straight line parallel to y–axis and passing through the point (–2, 5) will have slope as tan 90°.


(∵ Slope of a line is tan θ, where θ is the angle formed by the line with the x–axis)


Equation of a line passing through (x1,y1) is


(y–y1) = m(x–x1),where m is the slope.


Here m = tan 90°.


i.e.


(y–5) = tan 90°(x–(–2))


⇒


⇒ 0(y–5) = x + 2


⇒ 0 = x + 2


or x + 2 = 0

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