Q1 of 112 Page 150

Find the area of the triangle formed by the points
(5, 2), (3, –5) and (–5, –1)

(5, 2), (3, –5) and (–5, –1)

Let A (–5, –1) B (3, –5) and C (5, 2) be the vertices of triangle.

Area of triangle =

x₁ = –5, x₂ = 3 and x₃ = 5

y₁ = –1, y₂ = –5 and y₃ = 2

= 32 sq. units

Find the length of the medians of the triangle whose vertices are (1, –1), (0, 4) and (–5,3).

Find the area of the triangle formed by the points

(0, 0), (3, 0) and (0, 2)

Find the area of the triangle formed by the points

(–4, –5), (4, 5) and (–1, –6)

Vertices of the triangles taken in order and their areas are given below. In each of the following find the value of a.

Vertices: (0, 0), (4, a), (6, 4)

Area (in sq. units): 17

Find the area of the triangle formed by the points(5, 2), (3, –5) and (–5, –1)