Q8 of 112 Page 163

Find the equation of the straight line passing through the points

(i) (–2, 5) and (3, 6) (ii) (0, –6) and (–8, 2)

The equation of the line passing through the two given (x1, y1) and (x2,y2)points is given by form



(i) Here, (–2,5) and (3,6) are tow given points


The required equation is




5y –25 = x + 2


x–5y + 27 = 0


(ii) Here two points are (0, –6) and (–8, 2)


The equation is given by




–8y – 48 = 8x


x + y + 6 = 0 (dividing the whole equation by 8)


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