Q12 of 112 Page 168

The straight line 4x + 3y – 12 = 0 intersects the y– axis at

When the straight line 4x + 3y – 12 = 0 intersects the y– axis ,then the x coordinate of that point is 0.Thus the point is(0,y).


Now we will substitute (0,y) in the equation for the straight line


4x + 3y – 12 = 0.


⇒ 4(0) + 3y–12 = 0


⇒ 3y–12 = 0


⇒ 3y = 12


⇒


Hence the intersection point is (0,4).

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