Q1 of 112 Page 150

Find the area of the triangle formed by the points

(–4, –5), (4, 5) and (–1, –6)

(–4, –5), (4, 5) and (–1, –6)


Let A (–4, –5) B (–1, –6) and C (4,5) be the vertices of triangle.


Area of triangle =


x1 = –4, x2 = –1 and x3 = 4


y1 = –5, y2 = –6 and y3 = 5







= 19 sq. units


More from this chapter

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1

Find the area of the triangle formed by the points

(0, 0), (3, 0) and (0, 2)

 1

Find the area of the triangle formed by the points

(5, 2), (3, –5) and (–5, –1)

 2

Vertices of the triangles taken in order and their areas are given below. In each of the following find the value of a.

Vertices: (0, 0), (4, a), (6, 4)


Area (in sq. units): 17

 2

Vertices of the triangles taken in order and their areas are given below. In each of the following find the value of a.

Vertices: (a, a), (4, 5), (6, –1)


Area (in sq. units): 9