Find the slope of the straight line
3x + 4y – 6 = 0
Here we have the straight line : 3x + 4y –6 = 0
The slope intercept form is y = mx + b, where m is the slope and b is the y intercept.
Therefore, 3x + 4y –6 = 0
⇒ 4y + 3x = 6
⇒ 4y = 6–3x
⇒
(Divide both sides of the equation by 4)
⇒ ![]()
Now we will rewrite it in the slope intercept form
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Hence according to the slope intercept form, y = mx + b
m i.e. slope is
.
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