In each of the following, find the value of k for which the given points are collinear.
(k, k), (2, 3) and (4, – 1)
(k, k) (2, 3) and (4, –1)
Area of triangle = ![]()
x1 = k, x2 = 2 and x3 = 4
y1 = k, y2 = 3 and y3 = –1
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ 7k – 2 – k – 12 = 0
⇒ 6k – 14 = 0
⇒ 6k = 14
⇒ ![]()
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