The centre of a circle is (–6, 4). If one end of the diameter of the circle is at (–12, 8), then the other end is at

Question

Philoid · Accepted Answer

Here the centre of a circle is (–6, 4) and one end of the diameter of the circle is at (–12, 8).

As (–6,4) is the center of the circle it becomes the mid –point

of the diameter.

∴ is the mid–point or the center of the circle.

∴)

⇒ and

⇒ x1–12 = –6×2 = –12

⇒ x1 = –12 + 12 = 0

Now,

⇒ y1 + 8 = 4×2

⇒ y1 = 8–8 = 0

Hence the other end of the diameter is (0,0).