Q15 of 112 Page 163

Find the equation of the straight line passing through the point (5, –3) and whose intercepts on the axes are equal in magnitude but opposite in sign.

Let the x intercept be ‘a’. it is given the y intercept is equal in magnitude but opposite in sign


So y intercept = ‘–a’


The equation of the line using the intercept form is



⇒


⇒


⇒ x–y = a


The point (5, –3) lie son this line, thus it satisfies the given equation of the line


5 –(–3) = a


⇒ a = 8


The equation of the line is


x– y – 8 = 0


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