Find the product of the following :
(2x + 3y) (x2 – xy + y2)
2x × (x2 – xy + y2) + 3y × (x2 – xy + y2)
⇒ (2x × x2 – 2x × xy + 2x × y2) + (3y × x2 -3y × xy + 3y× y2)
⇒ (2x2 + 1 – 2x1 + 1y + 2xy2) + (3yx2 -3xy1 + 1 + 3y2 + 1)
(∵ an + m = an × am)
⇒ (2x2 + 1 – 2x1 + 1y + 2xy2) + (3yx2 -3xy1 + 1 + 3y2 + 1)
⇒ (2x3 – 2x2y + 2xy2) + (3yx2 -3xy2 + 3y3)
⇒ 2x3 – 2x2y + 3x2y + 2xy2 -3xy2 + 3y3
⇒ 2x3 (- 2 + 3)x2y + (2-3)xy2 + 3y3
⇒ 2x3 + x2y - xy2 + 3y3
Couldn't generate an explanation.
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