Q3 of 157 Page 30

Factorize:
mx – my – nx + ny

Given mx – my – nx + ny =(m × x – m × y + ( – n) × x + n × y)

Taking m common from 1^st and 2^nd term and ( – n) from 3^rd and 4^th,

⇒ mx – my – nx + ny = m (x – y) + ( – n)(x – y)

⇒ mx – my – nx + ny = (m – n)(x – y)

Factorize:

a²x + abx + ac + aby + b²y + bc

Factorize:

ax³ – bx² + ax – b

Factorize:

2m³ + 3m – 2m² – 3

Factorize:

a² + 11b + 11ab + a

Questions · 157

1. Algebra

1 1 1 1 1 1 1 2 3 4 5 6 1 2 3 4 5 5 5 5 5 6 6 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 4 4 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 5 5 5 5 5 6 6 7 8 9 10 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 4 4 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 5 5 5 1 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2

Factorize:mx – my – nx + ny