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Q2 of 157 Page 30

Factorize the following expressions :

2a5b3 – 14a2b2 + 4a3b

Given 2a5b3 – 14a2b2 + 4a3b = (2a2b×a3b2 – 2a2b×7b + 2a2b×2a)


Taking 2a2b common,


2a5b3 – 14a2b2 + 4a3b= 2a2b (a3b2 – 7b + 2a)


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Questions · 157
1. Algebra
1 1 1 1 1 1 1 2 3 4 5 6 1 2 3 4 5 5 5 5 5 6 6 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 4 4 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 5 5 5 5 5 6 6 7 8 9 10 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 4 4 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 5 5 5 1 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2
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