Factorize:

2m³ + 3m – 2m² – 3

Given 2m³ + 3m – 2m² – 3=(m × 2m² + m × 3 + ( – 1) × 2m² + ( – 1) × 3)

Taking m common from 1^st and 2^nd term and ( – 1) from 3^rd and 4^th,

⇒ 2m³ + 3m – 2m² – 3= m (2m² + 3) + ( – 1)(2m² + 3)

⇒ 2m³ + 3m – 2m² – 3= (2m² + 3)(m – 1)