Q2 of 95 Page 5

In figures (i) and (ii), DE || BC. Find EC in (i) and AD in (ii).

(i)


Given: DE || BC



[by basic proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.]


[given: AD= 1.5cm, DB =3cm & AE =1cm]





⇒ EC = 2cm


(ii)



Given: DB = 7.2 cm, AE = 1.8 cm and EC = 5.4 cm


and DE || BC



[by basic proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.]






⇒ AD = 2.4cm


More from this chapter

All 95 →
7

State whether the following pair of polygons are similar or not.

 1

In ΔABC, P and Q are two points on AB and AC respectively such that PQ || BC and , then find.

3

In a ΔABC, DE || BC, where D is a point on AB and E is a point on AC, then

(i) =……… (ii) =………


(iii) =……… (iv) =………

 4

If in Δ ABC, DE || BC and DE cuts sides AB and AC at D and E respectively such that AD: DB = 4: 5, then find AE: EC.