In the given figure BC = 5 cm, AC = 5.5 cm and AB= 4.6 cm. P and Q are points on AB and AC respectively such that PQ || BC. If PQ = 2.5 cm, find other sides of ΔAPQ.

Given: PQ || BC
To find: AP and AQ
Since, PQ || BC, AB is transversal, then,
APQ =
ABC [by corresponding angles]
Since, PQ || BC, AC is transversal, then,
APQ =
ABC [by corresponding angles]
In
APQ and
ABC
∠APQ = ∠ABC
∠AQP = ∠ACB
∴
APQ ≅
ABC [by AAA similarity]
Since, the corresponding sides of similar triangles are proportional
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⇒AP = 2.3
Now, taking ![]()
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⇒AQ = 2.75
Therefore, AP = 2.3cm and AQ = 2.75cm
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