In the figure DE || BC. If DE = 4 cm, BC = 8 cm and area (ΔADE) = 25 sq. cm, find the area of ΔABC.

Given: DE || BC
DE = 4cm, BC = 8cm and area (
ADE) =25 sq. cm
In
ABC and
ADE
∠B = ∠D [∵ DE || BC and AB is transversal,
Corresponding angles are equal]
∠C = ∠E [∵ DE || BC and AC is transversal,
Corresponding angles are equal]
∠BAC =∠DAE [common angle]
∴
ABC ~
ADE [by AAA similarity]
Now, we know that, the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.
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[given]
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⇒ ar(
ABC) = 25×4
⇒ ar (
ABC) = 100cm2
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