In the given figure, DE || BC and DE : BC = 4 : 5. Calculate the ratio of the areas of ΔADE and the trapezium ΔCEDB.

It is given that DE || BC and DE : BC = 4 : 5
Let ∆ ADE and ∆ABC
∠ADE = ∠ABC [corresponding angles]
∠AED = ∠ACB [corresponding angles]
∴ ∆ ADE ~ ∆ABC [by AA similarity]
We know that the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.
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Subtracting 1 from both the sides, we get
[given]
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