In the given figure, QA and PB are perpendiculars to AB. If AO = 10 cm, BO = 6 cm and PB = 9 cm, find AQ.


Let us take
OAQ and
OBP
∠AOQ = ∠BOP (vertically opposite angles)
∠OAQ = ∠OBP (each 90°)
∴
OAQ ~
OBP (by AA similarity criterion)
Given: AO = 10 cm, BO = 6 cm and PB = 9 cm
As,
OAQ ~
OBP
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⇒AQ = 15cm
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