In the given figure, if ∠A = ∠C, then prove that Δ AOB ~ Δ COD

Given: ∠A = ∠C
To Prove:
AOB ~
COD
Let us take
AOB and
COD
∠A = ∠C (given)
∠AOB = ∠COD (vertically opposite angles)
∴
AOB ~
COD (by AA similarity criterion)
Hence Proved
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