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5. Triangles
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Q6 of 95 Page 5

In the adjoining figure, AD = 2 cm, DB = 3 cm, AE = 5 cm and DE || BC, then find EC.

Given: AD = 2cm, DB =3cm, AE = 5cm

and DE || BC


Basic Proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.


So, by basic proportionality theorem





⇒ EC = 7.5 cm


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4

If in Δ ABC, DE || BC and DE cuts sides AB and AC at D and E respectively such that AD: DB = 4: 5, then find AE: EC.

5

In the adjoining figure, DE || BC. Find x.

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In the adjoining figure, DE || BC, AD = 2.4 cm, AE = 3.2 cm, CE = 4.8 cm, find BD.

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If DE has been drawn parallel to side BC of ΔABC cutting AB and AC at points D and E respectively, such that , then find the value of .

Questions · 95
5. Triangles
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