In the given figure, ΔABC and ΔDEF are similar, BC = 3cm, EF = 4 cm and area of ΔABC = 54 sq cm. Determine the area of ΔDEF.


Given: ΔABC ~ ΔEF, BC = 3cm, EF = 4 cm
and area of ΔABC = 54 sq cm
We know that, the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.
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[given]
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⇒ ar (∆DEF) = 96cm2
Couldn't generate an explanation.
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