In the given figure, if PQ || RS, prove that ΔPOQ ~ Δ SOR.

Given: PQ || RS
To Prove:
POQ ~
SOR
Let us take
POQ and
SOR
∠OPQ = ∠OSR (as PQ || RS, Alternate angles)
∠POQ = ∠ROS (vertically opposite angles)
∠OQP = ∠ORS (as PQ || RS, Alternate angles)
∴
POQ ~
SOR (by AAA similarity criterion)
Hence Proved
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