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5. Triangles
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Q14 of 95 Page 6

In the given figure, find ∠P.

From the figure,





Hence,


Now it can be seen that both the triangles are similar as the corresponding sides are propotional.


From the figure we can see that,


∠ P = ∠ C


From ΔABC,


∠ A + ∠ B + ∠ C = 180°


60° + 80° + ∠ C = 180°


∠ C = 180° – 140°


∠ C = 40°


Hence, ∠ P = 40°


More from this chapter

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12

In the given figure, ∠1 = ∠2 and , prove that ΔACB ~ ΔDCE

13

In an isosceles ΔABC with AC = BC, the base AB is produced both ways to P and Q such that AP x BQ = AC2. Prove that : ΔACP ~ ΔBQC

15

P and Q are points on the sides AB and AC respectively of a ΔABC. If AP = 2 cm, PB = 4 cm, AQ = 3 cm and QC = 6 cm, show that BC = 3 PQ.

16

P and Q are respectively the points on the sides AB and AC of a ΔABC. If AP = 2 cm, PB = 6 cm, AQ = 3 cm and QC = 9, Prove that BC = 4PQ.

Questions · 95
5. Triangles
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