Q4 of 95 Page 5

If in Δ ABC, DE || BC and DE cuts sides AB and AC at D and E respectively such that AD: DB = 4: 5, then find AE: EC.


Given: DE || BC


and


To find: AE: EC


Given: DE || BC


Basic Proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.


[by basic proportionality theorem]



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2

In figures (i) and (ii), DE || BC. Find EC in (i) and AD in (ii).

 3

In a ΔABC, DE || BC, where D is a point on AB and E is a point on AC, then

(i) =……… (ii) =………


(iii) =……… (iv) =………

 5

In the adjoining figure, DE || BC. Find x.

 6

In the adjoining figure, AD = 2 cm, DB = 3 cm, AE = 5 cm and DE || BC, then find EC.