Q15 of 95 Page 6

ΔABC is right angled at A and AD ⊥ BC. If BC = 13 cm and AC = 5 cm, find the ratio of the areas of ΔABC and ΔADC.

Given: AD ⊥ BC

and BC = 13 cm and AC = 5 cm


Let ABC and ADC


∠A = ∠D [each 90°]


∠C = ∠C [common angle]


∴ ABC ~ ADC [by AA similarity]


We know that, the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.





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