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5. Triangles
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Q7 of 95 Page 5

In the adjoining figure, DE || BC, AD = 2.4 cm, AE = 3.2 cm, CE = 4.8 cm, find BD.

Given: AD = 2.4cm, AE = 3.2cm and EC = 4.8cm

and DE || BC


Basic Proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.


So, by basic proportionality theorem






⇒ DB = 3.6 cm


or BD = 3.6 cm


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If DE has been drawn parallel to side BC of ΔABC cutting AB and AC at points D and E respectively, such that , then find the value of .

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Questions · 95
5. Triangles
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