The corresponding altitudes of two similar triangles are 6 cm and 9 cm respectively. Find the ratio of their areas.

Given: AM = 6cm and DN = 9cm
Here, ΔABC and ΔDEF are similar triangles
We know that, in similar triangles, corresponding angles are in the same ratio.
⇒∠A = ∠D, ∠B = ∠E and ∠C = ∠F ……(i)
∠B = ∠E [from (i)]
and ∠M = ∠N [each 90°]
∴
ABC ~
DEF [by AA similarity]
So,
……(ii)
We know that, the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.
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[from (ii)]
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