Q24 of 95 Page 6

In the given figure, ∠CAB =90° and AD ⊥ BC. Show that ΔBDA ~ ΔBAC. If AC = 75 cm, AB = 1 cm and BC = 1.25 cm, find AD.

Given: CAB =90° and AD BC

and AC = 75 cm, AB = 1 cm and BC = 1.25 cm


Now, In ADB and CAB


∠ADB = ∠CAB [each 90°]


∠ABD = ∠CBA [common angle]


∴ ADB ~CAB [by AA similarity]


Since the triangles are similar, hence corresponding sides are in proportional.




⇒ AD = 60cm


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