In a ΔABC, DE || BC, where D is a point on AB and E is a point on AC, then
(i)
=……… (ii)
=………
(iii)
=……… (iv)
=………

(i) Given: DE || BC
Basic Proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.
[by basic proportionality theorem]
(ii) Basic Proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio.
By basic proportionality theorem, we know that
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(iii) From part (i), we know that ![]()
On adding 1 to both the sides, we get
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(iv) From part (iii), we have ![]()
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