Solve the following system of equations by elimination method:

3x – 5y – 4 = 0

9x = 2y + 7

Given pair of linear equations is

3x – 5y – 4 = 0 …(i)

And 9x = 2y + 7 …(ii)

On multiplying Eq. (i) by 3 to make the coefficients of x equal, we get the equation as

9x – 15y – 12 = 0 …(iii)

On subtracting Eq. (ii) from Eq. (iii), we get

9x – 15y – 12 – 9x = 0 – 2y – 7

⇒ – 15y + 2y = – 7 + 12

⇒ – 13y = 5

On putting in Eq. (ii), we get

Hence, and , which is the required solution.