Let the two numbers be x and y.
According to the question,
x + y = 15 …(i)
…(ii)
Eq. (ii) can be re - written as
…(iii)
On putting the value of
in Eq. (iii), we get
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⇒ xy = 50
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On putting the value of
in Eq. (i), we get
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⇒ 50 + y2 = 15y
⇒ y2 – 15y + 50 = 0
⇒ y2 – 10y – 5y + 50 = 0
⇒ y(y – 10) – 5(y – 10) = 0
⇒ (y – 5)(y – 10) = 0
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Hence, the two numbers are 5 and 10.
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