Solve the following system of equations by elimination method:

3x + 4y = 10

2x – 2y = 2

Given pair of linear equations is

3x + 4y = 10 …(i)

And 2x – 2y = 2 …(ii)

On multiplying Eq. (i) by 2 and Eq. (ii) by 3 to make the coefficients of x equal, we get the equation as

6x + 8y = 20 …(iii)

6x – 6y = 6 …(iv)

On subtracting Eq. (iii) from Eq. (iv), we get

6x – 6y – 6x – 8y = 6 – 20

⇒ – 14y = – 14

⇒ y = 1

On putting y = 1 in Eq. (ii), we get

2x – 2(1) = 2

⇒ 2x – 2 = 2

⇒ x = 2

Hence, x = 2 and y = 1 , which is the required solution.